In order to show all of the work for the problem, the TI-89 uses a matrix to hold the divisor, the dividend, the quotient, the remainder, and all of the rest of the computations. For example consider the problem on the left, and its representation in polydiv on the right.
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Figure 1 is the result of pressing
the ![]() ![]() ![]() ![]() ![]() |
![]() | The actions of Figure 1 have pasted the name of our program, polydiv, into the command line of the calculator. In addition, the calculator has appended the required left parenthesis. There are no parameters for the polydiv program. Therefore, we can complete the command by supplying the matching right parenthesis. |
![]() | In Figure 3 we have completed the command
by pressing the ![]()
Now to begin the program we press the |
![]() | The polydiv program prompts us for the DIVISOR LIST.
We respond by entering
![]() We press the |
![]() | The polydiv program displays the initial matrix in Figure 5.
At this point the initial division has been done. That is, the program
reflects the problem at the stage of completing the initial division, namely,
![]() ![]() |
![]() | In Figure 6 the program has taken another step, determining the
second coefficient in the quotient. In this case, that is really all that there is to the
problem. Again the program is in a paused state so that we can move around in the
matrix if need be.
And, indeed, we can not see the bottom row of the matrix.
Therefore, we press the
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![]() | Here we see the rest of the matrix.
Having seen all of the problem we press
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![]() | Once the program has reached the end of the division,
the polydiv program displays
the menu shown in Figure 8. This allows us to
start a new problem by pressing 0 end the polydiv program by pressing 1 show the answer to the last problem by pressing 2. |
Let us look at another problem, namely,
![]() | We left Figure 8 by pressing the
![]() ![]() |
![]() | Pressing ![]() ![]() |
![]() | Figure 11 shows the calculator display after the second cycle
of the division algorithm. The second coefficient of the quotient
has been computed to be " 1" and
the corresponding portion of the division algorithm has been completed.
Press
![]() |
![]() | Again, we can use the ![]() Press
|
![]() | Figure 13 shows the top portion of the final matrix.
Again, we can use the ![]() |
![]() | Here is the lower portion of the matrix. The problem is done. If we press the ENTER the program will display the options to do a new problem, quit, or re-display the current matrix. |
Here is one more example:
![]() | In Figure 15 we have pressed ![]() |
![]() | Press ![]() |
![]() | Press ![]() |
![]() | Press ![]() ![]() |
![]() | In Figure 19 we can see the rest of the matrix. We press the
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![]() | Now we can see the matrix after the fourth and final step.
However, now we are missing both the bottom of the
matrix and the right side of the matrix.
We can use both the ![]() ![]() |
![]() | Figure 21 shows the rest of the matrix.
We can press the ![]() |
![]() | In Figure 22 we see the conclusion of the
program. We have responded to the menu by pressing the
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PRECALCULUS: College Algebra and Trigonometry
© 2000 Dennis Bila, James Egan, Roger Palay