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Figure 1 is the result of pressing
the ![]() ![]() ![]() |
![]() | The actions in Figure 1 pasted the command
prgmPOLYDIV1 onto the screen. Now we are ready
to press the ![]() |
![]() | The POLYDIV1 program prompts us for the DIVISOR LIST.
We respond by entering
![]() We press the |
![]() | The POLYDIV1 program displays the initial matrix in Figure 4.
At this point the initial division has been done. That is, the program
reflects the problem at the stage of completing the initial division, namely,
![]() ![]() |
![]() | In Figure 5 the program has taken another step, determining the
second coefficient in the quotient. In this case, that is really all that there is to the
problem. Again the program is in a paused state so that we can move around in the
matrix if need be.
For this problem we can see all of the answer on the screen.
Therefore, we do not need to look at any hidden values. We press
![]() |
![]() | Once the program has reached the end of the division,
the POLYDIV1 program displays
the menu shown in Figure 6. This allows us to
start a new problem by pressing 0 end the POLYDIV1 program by pressing 1 show the answer to the last problem by pressing 2. |
Let us look at another problem, namely,
![]() | We left Figure 6 by pressing the
![]() ![]() |
![]() | Pressing ![]() ![]() |
![]() | Figure 9 shows the calculator display after the second cycle
of the division algorithm. The second coefficient of the quotient
has been computed to be " 1" and
the corresponding portion of the division algorithm has been completed.
Press
![]() |
![]() | In the earlier Figures we could see all that we needed to see on the
screen.
Now, in Figure 10, we can see some of the values but we are missing the rightmost
numbers and the bottom numbers. Because the program is paused, we can use the cursor keys to
move around on the screen. For example,
we can press the ![]() |
![]() | Figure 11 displays the right side of the matrix.
We can use the ![]() |
![]() | Now that we can see the bottom of the matrix we note that the problem is done. If we press the ENTER the program will display the options to do a new problem, quit, or re-display the current matrix. |
Here is one more example:
![]() | In Figure 13 we have pressed ![]() |
![]() | Press ![]() ![]() |
![]() | Having seen the entire DIVIDEND,
we press ![]() |
![]() | Figure 16 shows the matrix after the second step. Note that we can not even see, in Figure 16, the second coefficient of the quotient. |
![]() | We use the ![]() |
![]() | To move from Figure 17 to Figure 18 we
press ![]() ![]() ![]() |
![]() | At this point all of the updates from the program are happenning
in matrix cells that are off the screen. As it turns out, at this point
we are really done with the problem, but we do not know it.
We press ![]() |
![]() | Figure 20 shows us the bottom of the matrix, and the menu options.
We need to go back to see to top right of the matrix
to see the rest of the quotient, and the bottom right
of the matrix, to see the remainder.
Therefore, we select option 2 to show the matrix again.
When we follow this by pressing ![]() ![]() |
![]() | Figure 21 shows us the rest of the quotient.
We can press the ![]() |
![]() | Finally, Figure 22 shows us the remainder.
If we were to follow this by presssing the ![]() |
PRECALCULUS: College Algebra and Trigonometry
© 2000 Dennis Bila, James Egan, Roger Palay