Figure 2
| Figure 2 shows the values that had been assigned, at some earlier time,
to the variables x,
y, and z, namely, x holds the value 5,
y holds the value 6, and z holds the
value 9. The values for x and z would have been substituted into the
equation by the "solve" command, and then the value of y
could be determined from the resulting values.
Note that the value assigned to y did not affect the answer
to the
solve(
x^2*y+z*( ^{– }y–1)=4(x+z),y)
command. If we want to solve the original
problem as it was done in the textbook, we need to clear those variables. |